Internati
o
nal
Journal of Ele
c
trical
and Computer
Engineering
(IJE
CE)
Vol
.
4
,
No
. 3,
J
une
2
0
1
4
,
pp
. 35
9~
36
5
I
S
SN
: 208
8-8
7
0
8
3
59
Jo
urn
a
l
h
o
me
pa
ge
: h
ttp
://iaesjo
u
r
na
l.com/
o
n
lin
e/ind
e
x.ph
p
/
IJECE
GUI ba
se
d Testing
To
o
l
fo
r Tra
n
sfor
mer
K.
S
u
ryase
n
, K.V. Devad
a
s,
Haris
h
A.
Departem
ent
of
Ele
c
tri
cal
and
E
l
ectron
i
cs
Eng
i
ne
ering,
K.V.G.C
.
E. S
u
l
lia
, D
.
K.
Article Info
A
B
STRAC
T
Article histo
r
y:
Received Nov 27, 2013
Rev
i
sed
Mar
16
, 20
14
Accepte
d Apr 2, 2014
The ob
jec
tive
of
this p
a
per
is to
de
velop an
edu
cational toolbox
using GUI
for analy
s
is of
transformers for stude
nts and lectur
ers. GUI figure file
is
develop
e
d for
Open Cir
c
uit & S
hort Ci
r
c
uit Tes
t
, Sumpner’s Test, All d
a
y
effic
i
enc
y
(
E
ner
g
y
eff
i
ci
enc
y
) o
f
tran
sformer and parallel oper
a
tion of two
transformers. All this k
i
nds of
probl
ems consists of var
i
ous methods of
m
a
them
atic
al c
a
l
cul
a
tion which
is difficult to
perform
by
us
ing m
a
nual
cal
cula
tion (for
m
ula and cal
cu
lator)
. The
exi
s
tence of th
is
educa
tiona
l
toolbox will help the user
to
calcul
ate the parameter hen
ce
the calculatio
n
becom
e
fas
t
er
an
d eas
i
e
r.
The
us
e
r
can
ent
e
r
the d
a
ta
and ob
tain
ed
the
res
u
lts
quickl
y
in the
f
o
rm
of data or
figures
. Th
e s
t
u
d
ents
can
als
o
obs
erve the
effect of
variation of inpu
t par
a
meters
on per
f
or
mance of
transf
ormer. This
educational
toolbox was dev
e
lop
e
d b
y
using
MATLAB software.
Keyword:
All day E
fficie
n
cy
Parallel op
erati
o
n
S.C. & O.C.Test
Transform
e
r T
e
sting
Transform
e
rs
Copyright ©
201
4 Institut
e
o
f
Ad
vanced
Engin
eer
ing and S
c
i
e
nce.
All rights re
se
rve
d
.
Co
rresp
ond
i
ng
Autho
r
:
Haris
h
. A,
Lect
ure
r
, K.
V.
G.
C
o
l
l
e
ge of
En
gi
neeri
n
g
,
Su
llia,
D.K. Karn
atak
a, Ind
i
a
Em
a
il: h
a
rish
ee1
3
@g
m
a
i
l
.co
m
1.
INTRODUCTION
Tran
sf
orm
e
r i
s
on
e o
f
t
h
e
m
o
st
im
portant el
ectrical
m
achines.
The
r
e are
vari
ous
tests conducted
on
t
r
ans
f
o
r
m
e
r t
o
det
e
rm
i
n
e t
h
e per
f
o
r
m
a
nce and e
q
ui
val
e
nt
c
i
rcui
t
of t
r
ans
f
orm
e
r. Ef
fi
ci
en
cy
and
reg
u
l
a
t
i
on a
r
e
very
i
m
port
a
nt
pe
rf
orm
a
nce
param
e
t
e
rs i
n
t
r
ans
f
o
r
m
e
r. T
h
ese
pa
ram
e
t
e
rs ca
n
be
o
b
t
a
i
n
ed
by
c
o
nd
u
c
t
i
n
g
Op
en
ci
rcu
it an
d short circu
it test and
b
y
Sum
p
n
e
r’s test.
Ope
n
circuit a
n
d short circuit
test are
used to a
n
alyses
the single phase
tran
sf
o
r
m
e
r for
obt
ai
ni
ng
t
h
e
equi
val
e
nt
ci
rc
ui
t
param
e
t
e
rs
and t
o
obt
ai
n t
h
e cha
r
act
eri
s
tic such as efficiency of
the tra
n
sform
e
r. In case of
ope
n ci
rcui
t
t
e
st
t
h
e sec
o
n
d
a
r
y
wi
n
d
i
n
g
of t
h
e t
r
a
n
s
f
o
r
m
e
r i
s
ke
pt
o
p
e
n
c
i
rcui
t
e
d a
n
d
pr
im
ary
i
s
exci
t
e
d
by
rated
voltage.
The
powe
r m
easure
d
unde
r t
h
is case is
Iron
lo
sses as the cu
rren
t
drawn
is less (2
t
o
5
%
o
f
rated
cur
r
ent
)
. I
n
case of sh
ort
ci
r
c
ui
t
t
e
st
t
h
e secon
d
a
r
y
wi
ndi
ng i
s
sh
ort
ci
r
c
ui
t
e
d an
d pri
m
ary
i
s
suppl
y
wi
t
h
a
rated c
u
rre
nt.
The
powe
r m
easure
d
under t
h
is case
is Co
p
p
e
r l
o
sses as
iron
loss is less (sup
p
l
y
v
o
ltag
e
i
s
less).
Usi
n
g these d
a
ta
we can
calcu
late effi
cien
cy an
d
regu
latio
n
fo
r an
y
lo
ad
con
d
ition
an
d power fact
o
r
[1
]
Whi
l
e
OC
an
d
SC
t
e
st
s on a t
r
ansf
o
r
m
e
r yi
eld i
t
s
equi
val
e
nt
ci
rcui
t
param
e
t
e
rs, t
h
ese can
not
be
us
e
d
for th
e h
eat run
test wh
erein
th
e pu
rp
ose is to
d
e
term
ine the steady temperat
ure ri
se if th
e tran
sformer was
fu
lly lo
ad
ed
con
tin
uou
sly; th
is is so b
ecau
s
e
u
n
d
e
r eac
h
of t
h
ese tests th
e po
wer loss to wh
ich
t
h
e tran
sfo
r
m
e
r
is sub
j
ected
is eith
er t
h
e core lo
ss
o
r
copp
er lo
ss bu
t
no
t bo
th. Th
e
way ou
t
o
f
this i
m
p
a
sse wi
th
ou
t
co
ndu
ctin
g an
actu
a
l test is th
e Su
m
p
n
e
r’s test wh
ich
can
on
ly b
e
co
ndu
cted
sim
u
ltan
e
o
u
sly o
n
two
id
en
tical
trans
f
o
r
m
e
rs [2
]
.
For a di
st
ri
but
i
on t
r
a
n
sf
o
r
m
e
r
m
easuri
ng p
o
w
er ef
fi
ciency yields wrong ju
d
g
i
n
g o
f
per
f
o
rm
ance of
trans
f
orm
e
r since these transform
e
rs s
eco
ndary su
pp
ly litt
l
e
o
r
no
lo
ad
mu
ch
o
f
th
e time d
u
ring
th
e d
a
y. Fo
r
th
is tran
sform
e
r th
e
p
r
im
ary i
s
en
er
gized all
twenty four hours a
nd c
o
pp
er loss
occ
u
rs
whe
n
the t
r
ans
f
orm
e
r
i
s
l
o
ade
d
. T
h
e
per
f
o
r
m
a
nce of s
u
c
h
t
r
an
sf
orm
e
rs i
s
com
p
are
d
o
n
t
h
e
basi
s o
f
ene
r
g
y
cons
um
ed duri
ng a
cer
tain
ti
m
e
p
e
r
i
od
, usu
a
lly a d
a
y o
r
24
ho
urs. To
d
e
term
ine energy effici
ency lo
ad cycl
e on the t
r
ans
f
orm
e
r
an
d pow
er f
act
o
r
is kno
wn
[3
].
Evaluation Warning : The document was created with Spire.PDF for Python.
I
S
SN
:
2
088
-87
08
IJEC
E V
o
l
.
4, No
. 3,
J
u
ne 2
0
1
4
:
35
9 – 3
6
5
36
0
If th
e
ratin
g
of an
ex
istin
g
t
r
an
sfo
r
m
e
r is
m
o
re th
an
th
e lo
ad
th
en
a seco
nd
tran
sformer
m
a
y b
e
co
nn
ected in
parallel.
Wh
en
o
p
e
rating
two
o
r
m
o
re t
r
an
sfo
r
m
e
rs in
p
a
rallel, th
eir satisfacto
r
y
p
e
rfo
r
man
c
e
req
u
ires
that t
h
ey
hav
e
(i
) sa
m
e
voltage
rati
o
(b
) sa
m
e
per
u
n
i
t
i
m
pedanc
e (c)
sam
e
pol
ari
t
y
(d
) sam
e
pha
se
sequence
. T
h
e
loa
d
division between the
several
tran
sfor
m
e
r
s
tak
e
s
by equ
a
l vo
ltage r
a
tio
s and un
equ
a
l
v
o
ltag
e
ratio
. In
case
of
eq
u
a
l
v
o
ltag
e
ratio
th
ere w
ill n
o
circu
l
ate current b
e
tween
t
w
o tran
sform
e
r. If th
e
i
m
p
e
d
a
n
ce of
b
o
t
h
tran
sfo
r
mer are sam
e
b
o
th
tran
sform
e
r
will sh
are a lo
ad
equ
a
lly. If th
ey h
a
v
e
same p
e
r
u
n
it im
p
e
d
a
n
c
e th
ey will sh
are a lo
ad
in
p
r
o
portio
n
to
t
h
eir ratin
g
s
. In
case o
f
u
n
e
qu
al v
o
ltag
e
ratio
,
th
en
a
circu
l
atin
g curren
t fl
o
w
s b
e
t
w
een
th
e two
tran
sfo
r
m
e
rs [4
].
To u
n
d
erst
a
nd
anal
y
s
i
s
of t
r
a
n
sf
orm
e
r i
n
co
m
put
ers one s
h
oul
d ha
ve g
o
o
d
m
a
t
h
em
at
i
c
al
kno
wl
ed
ge
an
d Prob
lem
s
o
lv
ing
sk
ills.
Mo
st of th
e t
o
p
i
cs requ
ire lo
t
o
f
calcu
latio
ns wh
ich
tak
e
s l
o
t of tim
e. To
an
alysis
pr
o
b
l
e
m
s
i
n
co
m
put
ers t
h
e us
er has t
o
g
o
f
o
r
pr
og
ram
m
i
ng.
Bu
t th
is way of an
alysis is com
p
lex
as it
in
vo
lv
es
chan
ge
of
p
r
o
g
ram
for e
v
e
r
y
case. I
n
or
der
t
o
re
duce
t
h
i
s
GU
I
based
t
o
ol
i
s
de
vel
o
pe
d f
o
r
t
h
e a
n
al
y
s
i
s
an
d
t
e
st
i
ng
of
Tra
n
sfo
r
m
e
rs i
n
M
A
TL
AB
/
G
UI e
nvi
ro
nm
ent
.
2.
MATLAB and GUI
2.
1 MAT
L
AB
MATLAB is
well k
nown
for its n
u
m
erical
p
r
o
b
l
em
so
lv
in
g
po
wer. Trad
itio
n
a
lly p
r
ogram
s written
by engi
neers
have very sim
p
le interfaces, a
n
d ofte
n only
the author is the one
who uses t
h
e program
once it
is
com
p
leted. There are occasions where a m
o
re polis
hed
us
e
r
interface
, spe
c
ifically
a
graphical user interface
(G
UI
) is
desire
d.
2.
2 Gr
ap
hi
cal
user Interface
A gra
p
hical us
er interface (GUI) is
a graphical display that contai
ns de
vices, or com
pone
nts, that
en
ab
le a
u
s
er t
o
perform
in
te
ractiv
e t
a
sks
.
The
GU
I c
o
m
p
o
n
e
n
t
s
can
be
m
e
nus, t
o
ol
ba
rs,
pu
sh
b
u
t
t
o
n
s
, ra
di
o
b
u
tton
s
, list box
es, and
slid
ers. In
M
A
TLAB, a GUI can
also
di
s
p
l
a
y
dat
a
i
n
t
a
b
u
l
a
r
f
o
r
m
or as pl
ot
s,
and
can
gr
o
u
p
rel
a
t
e
d
c
o
m
pone
nt
s.
A gra
p
hical user interface (GUI) is a pictorial
interface
to a program. A good GUI can m
a
ke
p
r
og
ram
s
easie
r to
u
s
e b
y
prov
id
ing
th
em
with
a co
n
s
istent ap
p
earan
ce an
d
with
in
tu
itiv
e. Th
e GUI sh
ou
ld
b
e
h
a
v
e
in
an
un
d
e
r
s
tand
ab
le an
d
pr
ed
ictab
l
e
m
a
n
n
e
r, so
t
h
at a u
s
er
know
s wh
at to
exp
ect wh
en
h
e
o
r
sh
e
p
e
rform
s
an
actio
n
.
For ex
am
p
l
e, wh
en a
m
o
u
s
e click
occu
rs on
a pu
sh
bu
tton
,
t
h
e
GUI
shou
ld
i
n
itiate th
e
act
i
on descri
be
d on
t
h
e
l
a
bel
of
t
h
e b
u
t
t
o
n
[
4
]
.
The t
h
ree
princ
i
pal elem
ents requi
red to c
r
ea
te a MATL
AB
Gra
p
hical Use
r
Interface
are:
i
)
C
o
m
pone
nt
s
.
Each i
t
e
m
on a
M
A
TL
AB
G
U
I
(
pus
h
but
t
o
n
s
, l
a
bel
s
,
edi
t
b
oxe
s, et
c.
) i
s
a
gra
p
hi
cal
com
p
o
n
e
n
t
.
T
h
e t
y
pes
of
com
pone
nt
s i
n
cl
ude g
r
ap
hi
ca
l
cont
rol
s
(
p
us
hb
ut
t
o
ns, edi
t
bo
xes
,
l
i
s
t
s
, sl
iders
,
et
c.), st
at
i
c
el
em
ent
s
(fr
am
es
and
t
e
xt
st
ri
n
g
s
)
, m
e
nus,
an
d a
x
es.
ii) Figu
res.
The c
o
m
pone
n
t
s of
a
GU
I m
u
st
be a
rra
n
g
ed
wi
t
h
i
n
a
fi
gu
re,
w
h
i
c
h i
s
wi
nd
ow
o
n
t
h
e c
o
m
put
e
r
sc
reen
.
iii) Callb
ack
s.
Fi
nal
l
y
, t
h
ere m
u
st
be so
m
e
way
t
o
per
f
o
r
m
an acti
on i
f
a user cl
i
c
k
s
a
m
ouse o
n
a but
t
o
n or t
y
pes
i
n
f
o
rm
at
i
on on
a key
boar
d
.
A m
ouse cl
i
c
k or a key
pres
s i
s
an event
,
and t
h
e M
A
T
L
AB
pr
o
g
ram
m
u
st
respon
d to
each
ev
en
t i
f
th
e prog
ram
is to
p
e
rfo
r
m
its fun
c
t
i
o
n
.
F
o
r
exam
pl
e, i
f
a
use
r
cl
i
c
ks
on
a
but
t
o
n
,
t
h
at
event m
u
st ca
use t
h
e MATL
AB c
ode
that i
m
ple
m
ents
th
e fu
n
c
tion
of the bu
tto
n to b
e
ex
ecu
ted
.
Th
e
co
d
e
ex
ecu
ted
in resp
on
se t
o
an
even
t is
known a
s
a call bac
k
.
T
h
ere m
u
st be
a
callb
ack
to imp
l
em
en
t th
e fun
c
tio
n
of each graphi
cal com
pone
nt
on the
GUI [5].
3.
STRU
CT
UR
E
OF DEVEL
O
PED GU
I
The G
U
I
fi
g
u
r
e
fi
l
e
i
s
devel
o
ped
fo
r anal
y
s
i
s
of t
r
a
n
sf
o
r
m
e
r by
(a)
O
p
en c
i
rcuit and s
h
ort
circuit test
(b
) Sum
pner
’
s
test (c) All day
effici
ency
of d
i
st
ri
but
i
o
n t
r
an
sfo
r
m
e
r (d) Par
a
l
l
e
l
operat
i
on
of t
r
a
n
sf
orm
e
r.
The
st
ruct
u
r
e o
f
t
h
e pr
op
ose
d
m
odel
i
s
as sh
o
w
n i
n
Fi
gu
re
1. He
re f
o
u
r
p
u
sh
b
u
t
t
o
ns are
t
h
ere fo
r t
h
i
s
m
odel
.
Wh
en
t
h
e
p
a
rti
c
u
l
ar
pu
shbu
tto
n is
p
r
essed
it
will
cau
se th
at
p
a
rticu
l
ar
figure file to op
en
.
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I
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sed
Tes
t
i
ng T
o
ol
f
o
r
T
r
an
sf
or
mer (
H
ari
s
h
A.)
36
1
Fi
gu
re
1.
St
r
u
c
t
ure
of
De
vel
o
ped
g
u
i
(a)
Open
circ
uit and short circuit
tes
t
Whe
n
S
.
C
an
d
O.C
.
t
e
st
p
u
s
h
but
t
o
n i
s
press
e
d o
n
t
i
m
l
a
b fi
gu
re fi
l
e
Fi
g
u
r
e 2 i
s
ope
ne
d.
Thi
s
fi
gu
re
file accepts rating
of tra
n
sformer (kva rating,
voltage
ratin
g), open circui
t test data and
short circuit test data
as i
n
p
u
t
s
. In t
h
e Loa
d
det
a
i
l
s
fract
i
on
of l
o
a
d
cu
rre
nt
(x
),
v
a
l
u
e of
po
we
r f
act
or an
d t
y
pe of l
o
a
d
(l
a
ggi
n
g
an
d
lead
in
g) is specified
.
After
en
tering
all
valu
es
p
r
ess d
i
sp
lay bu
tton
t
o
d
i
sp
lay th
e
eq
u
i
v
a
len
t
circu
it of
trans
f
orm
e
r as
seen on open and s
h
or
t circu
it. Th
is figure file also
cal
culates the val
u
e of efficienc
y
and
regu
latio
n fo
r t
h
e sp
ecified
load
co
nd
ition
s
.
Th
is
figu
re file also
d
i
sp
lays th
e
g
r
aph
o
f
efficien
cy v
e
rsu
s
lo
ad
cu
rr
en
t and
r
e
gu
latio
n
v
e
r
s
us
p
o
w
e
r
f
act
o
r
.
Th
is
f
i
gu
r
e
is as show
n in
Figu
r
e
3.
Figu
re
2.
O
p
e
n
circuit a
n
d
s
h
o
r
t circuit
fig
u
re
file
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o
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.
4, No
. 3,
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u
ne 2
0
1
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:
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9 – 3
6
5
36
2
Fi
gu
re
3.
Ef
fi
ci
ency
ve
rs
us l
o
ad c
u
r
r
ent
a
n
d
R
e
gul
at
i
o
n
ver
s
us
p
o
we
r
fact
or
an
gl
e
(b) Sum
pner
’
s
Test
Whe
n
t
h
e sum
pne
r’
s t
e
st
p
u
s
h
b
u
t
t
o
n i
s
p
r
es
sed
on
Ti
m
l
a
b fi
g
u
re
fi
l
e
Fi
g
u
re
4 i
s
ope
ne
d
.
Thi
s
fi
g
u
re
file accepts
rating
of tra
n
sformer (kva
rating, prim
ary
and
seconda
ry vol
tage
), Sum
pne
r’s
Test data
(Prim
a
ry
in
pu
t vo
ltag
e
,
To
tal No
lo
ad
cu
rren
t, Iron
loss fo
r
bo
th
t
r
a
n
sf
orm
e
r, Sec
o
nda
ry
s
h
o
r
t
ci
r
c
ui
t
e
d
vol
t
a
ge
,
Sh
ort
circuited c
u
rre
n
t, copper l
o
ss
es for
bot
h m
a
chines
) and l
o
ad
cond
itio
n
s
(fractio
n
of
lo
a
d
current, powe
r factor
an
d
ty
p
e
of load
lagg
ing
o
r
lead
in
g) as i
n
p
u
t
s. Afte
r en
t
e
ring
all th
e valu
es press
Execu
te pu
sh
bu
tto
n
t
o
d
i
sp
lay eq
u
i
v
a
len
t
circu
it
p
a
ra
m
e
ters Ro
,
Xo
an
d R2
eq
, X2
eq.
It will also
calcu
late t
h
e v
a
lu
e of efficien
cy
an
d reg
u
l
ation for th
is l
o
ad
co
nd
itio
ns. This figu
re
file
also
d
i
sp
lays the g
r
aph
o
f
efficien
cy v
e
rsu
s
lo
ad
cu
rr
en
t and
r
e
gu
latio
n
v
e
r
s
us
p
o
w
e
r
f
act
o
r
.
Th
is
f
i
gu
r
e
is as show
n in
Figu
r
e
5.
Fi
gu
re
4.
S
u
m
pne
r’
s Test
Fi
g
u
re
Fi
l
e
Evaluation Warning : The document was created with Spire.PDF for Python.
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J
ECE
I
S
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:
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8-8
7
0
8
GU
I
ba
sed
Tes
t
i
ng T
o
ol
f
o
r
T
r
an
sf
or
mer (
H
ari
s
h
A.)
36
3
Fi
gu
re
5.
Ef
fi
ci
ency
ve
rs
us l
o
ad c
u
r
r
ent
a
n
d
reg
u
l
a
t
i
o
n
ve
rs
us
po
we
r f
act
o
r
a
ngl
e
(c)
All day efficiency
of tr
ansfor
mer
Whe
n
t
h
e Al
l
-
day
ef
fi
ci
ency
pus
h
but
t
on i
s
press
e
d
o
n
Ti
m
l
a
b fi
g
u
re
fi
l
e
Fi
gu
re
6 i
s
ope
ne
d. T
h
i
s
fig
u
re file
acc
epts kva
ratin
g of
tra
n
sf
orm
e
r, Ir
o
n
losses and
fu
ll l
o
ad cop
p
e
r l
o
sses of th
e tran
sfo
r
m
e
r,
n
u
m
b
e
r
o
f
load
step
s. After
en
tering
n
u
m
b
e
r of lo
ad
step
s lo
ad
nu
m
b
er is in
itialised
to
th
is v
a
lu
e. The d
a
ily
lo
ad
v
a
riation
is en
tered
;
p
o
wer at th
is lo
ad
and
p
o
wer
facto
r
o
f
th
is load
is en
te
re
d.
After t
h
is, pre
ss save
b
u
tton
t
o
sav
e
th
is v
a
l
u
e.
Now ch
ang
e
po
p-u
p
m
e
n
u
to
enter d
a
ta
for
n
e
x
t
lo
ad
s. After en
teri
n
g
all the lo
ad
d
e
tails p
r
ess Ex
ecu
te
bu
tton
t
o
d
i
sp
lay to
tal
iron
lo
sses
, t
o
tal co
pp
er losses, to
tal
o
u
t
p
u
t
i
n
k
ilo
watt-ho
ur and
Ener
gy
ef
fi
ci
ency
o
f
t
h
e t
r
a
n
sfo
r
m
e
r. If t
h
e
dai
l
y
vari
at
i
on
i
s
not
e
n
t
e
red
f
o
r
24
h
o
u
r
s t
h
e
n
a wa
rni
n
g m
e
ssag
e
will b
e
d
i
sp
lay
e
d
wh
ich
is as
sh
own
in Fi
g
u
re 7
.
Figu
re
6.
All-
d
a
y
efficiency
(
E
ner
g
y
E
fficie
n
cy
)
fig
u
re
file
Evaluation Warning : The document was created with Spire.PDF for Python.
I
S
SN
:
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-87
08
IJEC
E V
o
l
.
4, No
. 3,
J
u
ne 2
0
1
4
:
35
9 – 3
6
5
36
4
Fi
gu
re 7.
W
a
rn
i
ng
M
e
ss
age
(d) P
a
rallel operati
on
of tr
ansformer
Whe
n
t
h
e Pa
ra
l
l
e
l
operat
i
o
n
pus
h
but
t
on i
s
press
e
d
o
n
Ti
m
l
a
b fi
g
u
re
fi
l
e
Fi
gu
re
8 i
s
ope
ne
d.
Thi
s
figure
file acce
pts
kva
rating
and im
pedance
of
bot
h tra
n
sf
orm
e
rs, loa
d
powe
r i
n
kva
or kW is s
p
ecifie
d
with
lo
ad
p
o
wer facto
r
with
lo
ad co
nd
ition
(lag
g
i
n
g
/
l
o
ad
i
n
g
)
. Now press Ex
ecu
t
e bu
tto
n
t
o
see
h
o
w two
transform
e
rs will shar
e
the
specified
loa
d
de
mand. The val
u
e of
real a
nd
reactive
power sha
r
ed by
bot
h the
t
r
ans
f
o
r
m
e
r i
s
di
spl
a
y
e
d a
nd
concl
u
si
o
n
i
s
d
i
spl
a
y
e
d as
which
tran
sform
e
r is lo
ad
ed
m
o
re. An
o
p
tion
is g
i
v
e
n
for ch
ang
i
ng
fro
m
eq
u
a
l vo
ltag
e
ratio
to un
eq
u
a
l
vo
ltag
e
ratio
.
Fi
gu
re
8.
Paral
l
el
ope
rat
i
o
n
o
f
t
w
o
t
r
a
n
sf
orm
e
rs
4.
CO
NCL
USI
O
N
A M
A
TLAB
/
GU
I
base
d e
ducat
i
o
n t
ool
has
bee
n
de
vel
o
ped
t
o
d
e
m
onst
r
at
e t
h
e t
e
st
i
ng
of
tran
sform
e
rs. Th
is GUI
will
d
e
m
o
n
s
trat
e testin
g
of tran
sfo
r
m
e
r b
y
o
p
e
n circu
it an
d
sho
r
t circu
it, sum
p
n
e
r’s
t
e
st
, al
l
day
ef
fi
ci
ency
and
p
a
ral
l
e
l
operat
i
on
of t
w
o t
r
a
n
sfo
r
m
e
rs. Thi
s
soft
wa
re p
r
ov
i
d
es a user
-f
ri
endl
y
interface t
o
he
lp the stude
n
t to an
alyze electrical
m
achines. After runni
ng t
h
e GUI the user
can sel
ect the
part
i
c
ul
a
r
t
e
st
i
ng
o
f
m
achi
n
es, ent
e
r t
h
e da
t
a
and
di
sp
lay
th
e resu
lts. Th
e effect of variatio
n
o
f
an
y
in
pu
t
param
e
ter can
also be
observed. St
ude
nt ca
n ve
rify s
o
lution
of any
proble
m
with this tool.
This i
n
terface can
be
use
d
as a
n
e
ducat
i
o
nal
t
ool
f
o
r a
n
al
y
s
i
s
o
f
el
ect
rical
m
achines
. T
h
e
onl
y requir
em
en
t for th
is is MATLAB.
REFERE
NC
ES
[1]
I.J. Nagr
ath
& D
.
P. Koth
ari,
“
Ele
c
trical
Mach
ines
”, T.M
.
H
.
4
th
Edition, 2010, pag
e
s: 81-84
[2]
Alexander
Lang
sdorf, “
Theory o
f
Alternating Cu
rrent Machin
es
”,
T.
M.
H.
2
nd
Edition, 2001
Evaluation Warning : The document was created with Spire.PDF for Python.
I
J
ECE
I
S
SN
:
208
8-8
7
0
8
GU
I
ba
sed
Tes
t
i
ng T
o
ol
f
o
r
T
r
an
sf
or
mer (
H
ari
s
h
A.)
36
5
[3]
B.L.
Ther
eja
&
A.K.Ther
aja
,
“
a textbook
o
f
Electrical
Technology
”, Volume II, Page: 1181
[4]
M.
G.
Say
,
“
th
e p
e
rformance and
design of alternating
current machines
”, Th
ird
edition, pag
e
s: 80
-
85
[5]
www.
mathwork
s.
com
BIOGRAP
HI
ES OF
AUTH
ORS
M
r
.
K.
Sury
a
se
n
receiv
ed B. Tech from co
llege of
engineering, JNT Univ
ersity
, Andhra
Pradesh. He had
10
y
ears of
indu
strial
exper
i
en
ce
. He
is
pres
en
tl
y
working as
As
s
i
s
t
ant P
r
ofes
s
o
r
in K.
V.
G.
College of Engineeri
ng, Sullia, Dakshina Kann
ada.
Hi
s area
of in
te
rest is Power
S
y
s
t
em
s
,
P
o
wer
Ele
c
troni
cs
, Ind
u
s
t
rial
Drives
,
El
ectr
i
ca
l M
a
chine
s
. He
is
a
lif
e m
e
m
b
er of IS
TE
.
Prof.
K
.
V. Dev
a
d
a
s
rece
ived
his B.
E.
from S
.
J.
C.
E.
M
y
sore
.
He receiv
ed his
M.Tech from
K.R.E
.
C.S
u
rathk
a
l. P
r
es
ent
l
y
w
o
rking as
a H
ead of the Departm
e
nt in K.V.G.Coll
ege of
Engine
ering,
Sullia
. He has a
tot
a
l te
aching
exper
i
en
ce of 24
years
.
His area of
inter
e
sts is Power
S
y
s
t
em
s
,
E
l
ec
tri
cal
M
achin
es
,
an
d P
o
wer El
ec
tro
n
ics
.
He
is
a
lif
e
m
e
m
b
er of IS
TE
& I
E
E
E
.
Mr. Haris
h
.
A
rece
ived his
B.E from
P
.
E.S
.
Coll
ege of E
ngineer
ing, M
a
nd
y
a
. P
r
es
ent
l
y
working as Lecturer in K.V.G.C
o
lleg
e
of Engin
eering
,
Sullia, D
a
kshina Kannad
a
. His area of
inter
e
s
t
is
P
o
wer
S
y
s
t
em
s
,
El
ectr
i
cal
M
achin
es
,
P
o
wer El
ec
tronics
.
He is
a
lif
e m
e
m
b
er of IS
TE
.
Evaluation Warning : The document was created with Spire.PDF for Python.